I was just minding my own business when all of a sudden, at the top of the page: 

What could possibly possess it to appear? 

Everyone it seems somebody known as 
 
mohammedroxx3 :
 
Has recovered a permanent specimen of zebra leggy. How he did this was he saw the beast and than replied to the post the wild leggy gave.
 
legacyme3 :
 
You have no hope now we have evidence of your existence and no matter what anybody trusted or above can see you.
 
Here is where he is.
 
https://www.vizzed.com/boards/thread.php?id=78911&ppp=20&page=1#1064459 
 
Now here is the photo I took.
 

there was a zebra on my profile today.

http://i.imgur.com/NC6AnLe.png?1

should I run now?

Gingercream1 : Oh my god..

I'm in more danger than you, my name is right next to that thing !  D=

I'm a master hunter, since I managed to catch the wild beast.

Check it out

Note - That puush will only last two months or so, so if you want to enjoy it forever, click here.

alexanyways : I remember that picture. Sad that that chat had to die. My little brother with his epic Lego Sword now has no job, as the company went into bankruptcy, and he has to find another job....

HELP!!! THE BLOODY ZEBRA HAS FOUND ME!!! HE IS ON MY PROFILE!!! * oof * Sorry guys, I couldn't get any proof. 



And going through this thread, why do most of the links not work? 

Has anyone ever considered actually talking to it????


legacyme3 : uh......hi? *gulp*

awesomeguy279 :

mohammedroxx3 : I did the same thing D=



Mega Mewtwo X : He didn't respond... maybe he's taking a while to plan what he's going to do to you...

Something seems awfully suspicious about this....

Check out this mutation

It's mutating.

Oddly enough I was a bit naive about the sightings of this...whatever it is...i mean i kill spiders with my hands so why is it a big deal. notably though it became one though as when i finally decided to speak to it, it spoke back.

Interestingly enough, I am not sure if I should be scared for my life or try feeding it a cookie...only time will tell.

This is so scary!!!!! He's gonna kill us in our sleep then paint us black and white!!!! It's horrid! Horrid I tell you!

He's been on my profile a lot lately. I am scared. Save me. 

One day, trainer EideticMemory discovered a wild legacyme3. He quickly attempted to close in on the creature, planning to capture and train it.

http://i.gyazo.com/90ea6a3ca3535c5db9b9f91c4ea5494b.png

As EideticMemory surrounded and closed in on the wild legacyme3, the legacyme3 used zebra in response.

http://i.gyazo.com/b3a5ea266bdbf23f6c614749caf4dd2d.png

It was super-effective! Trainer EideticMemory fainted!

mrfe :

That's no way to talk too an expert! I've been studying it since you were a wee lad...



...a little over a year ago.


However my efforts have yielded an upgrade to the pokeball. The summon-cage.

My research has led me to realize the summon cage works according to the equation below:

S = C/A = ln(C2)/ln(A2)

where
S = the number of summons needed
C = the natural log of C2 (ln(C2)); C2 = 1 - P1; P1 = the proportion of times that the summon-cage should succeed
A = the natural log of A2 (ln(A2)); A2 = 1 - the proportion of times the zebra form appears.

So in practice... say we want to have a 95% chance of catching it.

S = ln(0.05)/ln(0.99) = 298 summons needed.

Or if we want to have a 99.9% chance of catching it:

S = ln(0.001)/ln(0.99) = 688 summons needed

This zebra will be mine! (and its notifications will probably explode)

EideticMemory :

*remembers a couple weeks ago when we had a similar conversation*

RIP Leggy.

/notification summon[action=double]

Regardless, we shall catch this zebra...

mrfe :

What I have shown so far is merely the tip of the iceberg.

Wild Leggy is like an electron in the fact that it has wave particle duality.

In other words, it can be in two or more places at once. We're delving into quantum mechanics, of course.



(and you probably thought Leggy was reproducing with himself!)

This complicates matters considerably, since simply capturing one comes with the chance of capturing two.

In fact, this leads us to add an exponent of n to the equation.

S = C/A = ln(C2)/ln((1-P2^n)) where n is the number of Wild Leggy's we expect to catch.

Using our calculation of before:

688 summons = ln(C2)/ln((1-(.01^n)).

At n = 2, C2 = .9335.

That means with 688 summons, there's actually a 7.6% chance that we'll catch 2 Wild Leggy's (and 99.9% that we'll catch one).

Keeping our summon count at 688, At:
n = 3, C2 = 6.8776e-04 (0.07% chance of 3 Wild Leggy's)
n = 4, C2 = 6.8800e-06
n = 5, C2 = 6.8800e-08
n = 6, C2 = 6.8798e-10

It's very interesting indeed.

The question might be posed of where Wild Leggy is at any given moment. Since if you think of it, it's always existing SOMEWHERE, even if we don't know exactly where at that moment.

We'd have to invoke an altered Heisenberg's principle.

This is a Robertson–Schrodinger interpretation, but as we are dealing with wave-particle duality, we might try a wave mechanics interpretation.

Elementary, my dear mrfe. Elementary.

EideticMemory :

o.o

I...

I understand why I work at Taco Bell now.

#sodoisummonhimmoreornah

mrfe :

I actually just posted that so that someone will summon him 688 times.

Elementary, my dear mrfe. Elementary.

I think it also works only on visible summons, so that's unfortunate.

-

On another note, I wonder if we would consider this a half-zebra.

EideticMemory :
mrfe :
I really think bad things were too happen if somebody summoned him that many times. I don't think anybody in their right mind would do such a thing. So go ahead EM.