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03-23-26 09:08 AM

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Hard Riddle
Can you answer it?
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erty80s
02-04-11 07:20 PM
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03-12-11 05:15 PM
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Hard Riddle

 
A lady has 10 cats 3 drowned,2 cats are roadkill and 2 got lost .How many cats are living?
3
 
18.2%, 2 votes
I dont care
 
27.3%, 3 votes
what if the lost cats are dead
 
9.1%, 1 vote
5
 
45.5%, 5 votes
this riddle cant be resolved
 
0.0%, 0 vote
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02-04-11 07:20 PM
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So you think your brain is smart enough to solve my riddle?then try to solve it then.NOTE:the riddle isnt that hard

So you think your brain is smart enough to solve my riddle?then try to solve it then.NOTE:the riddle isnt that hard

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02-04-11 08:36 PM
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5 unless the lost cats are dead
5 unless the lost cats are dead
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02-07-11 02:18 PM
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I agree with linkman. If the lost cats are still alive then it makes 5 living cats.
I agree with linkman. If the lost cats are still alive then it makes 5 living cats.
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I agree with link and chaos she would have 5 unless the lost cats are dead.
I agree with link and chaos she would have 5 unless the lost cats are dead.
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5 2 are lost not dead ha i am to smart for your riddles...kidding
5 2 are lost not dead ha i am to smart for your riddles...kidding
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She has 10. Maybe they're all alive and those other ones are diversion cats .
She has 10. Maybe they're all alive and those other ones are diversion cats .
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The answer can vary from 5-7. If only one cat that is lost is dead, the answer is 6. Also, what if the drowned cats and roadkill cats get an afterlife spell put on them and become zombie cats? I think the answer is, in fact, 10.
The answer can vary from 5-7. If only one cat that is lost is dead, the answer is 6. Also, what if the drowned cats and roadkill cats get an afterlife spell put on them and become zombie cats? I think the answer is, in fact, 10.
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03-11-11 05:36 PM
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It's not much of a riddle. If the answer is not five, ten, or twelve cats, then the riddle is quite impossible. See, it never actually specifies that the lost, drowned and roadkill'd cats are actually hers. Furthermore, the question of how many cats are alive poses the same problem; her ownership of the cats in question is unspecified, meaning that the cats may be alive anywhere on earth. Even with the most basic Algebra, one cannot solve for two unknowns.

Let A represent the number of living cats.
Here is the equation provided the lost, drowned and roadkill'd cats belong to the woman:
A= 10-2-3-0{Lost cats, assuming they are not dead}
A= 5

Now, based on logic due to unstable grammar:
A= x-2-3-0
A= x-5
Thus, it is impossible to solve. Now, we can only be sure that A≤5, or A=[5,∞).
It's not much of a riddle. If the answer is not five, ten, or twelve cats, then the riddle is quite impossible. See, it never actually specifies that the lost, drowned and roadkill'd cats are actually hers. Furthermore, the question of how many cats are alive poses the same problem; her ownership of the cats in question is unspecified, meaning that the cats may be alive anywhere on earth. Even with the most basic Algebra, one cannot solve for two unknowns.

Let A represent the number of living cats.
Here is the equation provided the lost, drowned and roadkill'd cats belong to the woman:
A= 10-2-3-0{Lost cats, assuming they are not dead}
A= 5

Now, based on logic due to unstable grammar:
A= x-2-3-0
A= x-5
Thus, it is impossible to solve. Now, we can only be sure that A≤5, or A=[5,∞).
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03-12-11 05:15 PM
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heres my guess I DONT CARE...........unless u give me a cat
heres my guess I DONT CARE...........unless u give me a cat
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