Alright, I hope this hasn't already been done before...If you're stuck with any homework problems and just can't get through them...type them out, post a jpeg etc.  I'll try to answer them, I would hope that some of the Vizzed community would also answer some and this could be like a community study group of sorts.  
 
I suppose that I had primarily math and science type of subject matter in mind, but I don't really see why it would have to be limited to that.  I do think it's important to state which subject it's in, and fully include graphs, images, data, formulas given etc.  For this to be effective, posters must present the problem clearly and in its entirety.  

OK, to start this off...PHYSICS I

If the position is defined by the function s(t)=2x^3 + 3x^2 -7x + 5 .  What is the velocity v(t) at t=4s??  What is the acceleration a(t) at t=12s??

(Just for the record, I'm not just trying to get help on a homework problem myself.  I already passed Physics and know how to do this problem.)

Anyone out there know how to solve this or have a problem they're stuck on??

OK....the problem I posted was Physics, but not high school Physics.  This one required Calculus to solve.  These particular problems were pretty simple polynomials that can all be treated the same way when differentiating (finding the derivative.)  If you have any interest in learning a new Math skill and understanding mathematical relationships in the physical world, please, do read.

First we're given a polynomial expression that expresses the position of a particle in relation to time (x).

   s(x) = 2x^3 + 3x^2 - 7x + 5       So if we took its position at x = 3

                                                We'd get 2(3)(3)(3) + 3(3)(3) - 7(3) + 5 = 65 units

Anyone who's taken Algebra already knows how to plug in values for the variables.  Here's where the Calculus comes in....

d/dx[s(x)] = v(x) = 6x^2 + 6x - 7    If you look closely, you'll see that to derive the previous term you take the exponent of the variable
                                                            and multiply the variable by that value, while the exponent then decreases by one.  Also notice that
                                                            the derivative of a constant (or integer) is zero.

So if you are given the position, find the derivative and you will get the velocity.  If you take the derivative of the velocity, you will have the expression for acceleration.

v(x) = 6x^2 + 6x -7  So velocity at x = 4 would be.....    6(4)(4) + 6(4) - 7 = 113 units/sec.

a(x) = 12x + 6    So acceleration at x = 12 would be..... 12(12) + 6 = 150 units/sec.^2

I just hadn't seen any replies in a few days and figured maybe a lot of people on here haven't had much upper level math or sciences.  If anyone has any problems in any subject at any level, please post them here.  If I don't know how to do it, maybe someone on Vizzed does.  Go on, whatcha got??

OK....I gave it a couple weeks, and still nothing.  I'm just gonna try to let someone see this on the new posts in case there's a smarty pants out there.  I saw someone in the school forum ask if anyone needed any help in Chemistry.  So....

What is the electron configuration of Zinc (Zn)?

Full electron configuration?
1s2 2s2 2p6 3s2 3p6 3d10 4s2
I think you can also give it as 3d10 4s2 but I only took 1 year of chem so I don't know.

mlb789 : To express it as 3d10 4s2 you'd need to include the name of the noble gas located before that element to account for the noble gas part of the electron configuration. So an alternative way to express it would be [Ar] 3d10 4s2 (I think Argon is the noble gas before Zinc, but I'm not entirely sure).

megamanmaniac: Yeah, that's completely correct.  Awesome mlb789 and megamanmaniac.  Thanks for the responses!  I've been trying to get a scholastic discussion going on here, but people don't seem too interested so far.  Perhaps I should have structured this more like a trivia game and asked more general questions, and then asked respondents to post the next.  

Hmmmm....OK, I'll try another one.  What is the average and standard deviation of this set: 9,10,10,11,11,12,13,13 ? 

Anyone out there know how to solve this?  Feel free to Google or whatever you need to do, and add your own trivia style problem for us to solve.  OR, if you have any problems you're stuck on, please post them here. 

I'm supposed to memorize all traits (mass, number, and symbol) of the first 30 elements on the periodic table. It's easy for me when I'm trying to figure out other traits and it only gives me one trait to use. But memorizing all o it is harder. It's easy if I remember one of the three traits. But if one of those traits is wrong, the whole thing is screwed up. Other than that I have no trouble.

fireking1058 : You're doing that at 11 years old!? Where I live, we don't do that until 8th Grade, the grade I am currently in. Well, there is the possibility that you live in another country, but I kind of neglected to check your profile. Even so, that's still so young to be learning about that, at least I think so.

Kefka : Average is just a numerical average, so add it all up and divide by the amount of #s, or 8. Should be about 11.125.
For standard deviation, it's the square root of (the sum of the value (x) subtracted by the mean (x bar) over the amount of numbers minus 1). For these values, it would be about 1.4577.

fireking1058: Yeah, I've never had to memorize anything except for the full names when given the symbol.  That's easy enough, the full name is the Greek or Latin word for the element ie: Lead (Pb) is Plumbium, Iron (Fe) is Ferris, etc.  If you can remember their electron configuration, you can roughly estimate their atomic number, and for some of them, doubling that gives the approximate atomic mass (but these are not very reliable.)  OR...you could memorize which period and group they are in and assign those values that way.  I would just say, it seems the most practical to use flashcards and memorize those values for each of the 30.  I'm sure some of them will be very easy, like Carbon and Oxygen.  They are used a LOT, so its pretty easy to remember C....12.011g/mol is #6 and Oxygen....15.999g/mol is #8.  My advice would be to set aside the ones you know and practice those lightly, and really concentrate on those you're not as familiar with.  If you ever have questions about how to work with these, please feel free to post.  There's a lot to chemistry when working with reactions, bonding, Lewis dot structures, etc.  

mlb789 : Awesome work mlb789, that's exactly what I got when I worked it out.  I really appreciate the explanation of the steps too.  

OK, next up:  Using the Quadratic Formula x=[-b(+ or -) sqrt(b^2 - 4ac)]/2a  to solve for x in....y=3x^2 + 4x + 5

Um, did you mean for that last quadratic to not have any roots? It should never cross the x-axis. But, if we really wanted to graph it in the complex plane, final output should be (-4 +/- sqrt(-44))/6 which would be approximately (-4 +/- 2i(sqrt(11))/6