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College Algebra sucks.
I have a program I use to do equations that shows me the answers and the work. However it doesn't do word problems. One question is: "phyllis invested 12000$, a portion earning a simple interest rate at 4.5% per year and the rest earning 4% per year. After 1 year the total interest earned on these investments was 525$. how much money did she invest at each rate?" who names their kid phyllis for starters? and second, when will i need this in my life? but if you could please legitly show me the equation for this word problem, i might be able to solve it. (: 
Funguar Unknown Affected by 'Laziness' Position: Since: 011112 Last Post: 976 days Last Active: 956 days 

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I'll try to explain it as best as I can.
First off, you know that there are two numbers that add up to 12,000. So: x + y = 12000 Next you know that the interest rates per year, and the total interest after one year. So: .045*x + .04*y = 525 NOTE: It doesn't matter which variable is multiplied by which rate. Next you play with the first equation to get it in terms of one variable. So: y = 12000  x. NOTE: It doesn't matter which variable you subtract, I just tend to prefer working with x's. Next you substitute that into the interest equation. So: .045*x + .04*(12000x) = 525 Play with the numbers a little to make it easier to see what's going on. So: .045*x + (.04*12000)  (.04*x) = 525 Work that out a little. So: .045x  .04x + 480 = 525 Then: .005x = 45 Finally: x = 9000 Because x = 12000  y, that means that y = 3000. Plug both numbers into the equation that has the interest rates to check the answers and you'll see that it works. I hope that helps you, and just let me know if there was anything unclear or if you still don't understand something. 
The Reaper
Affected by 'Laziness' Position: Elite Since: 010911 From: soxfan849 Last Post: 40 days Last Active: 1 day 

 
thanks!

Funguar Unknown Affected by 'Laziness' Position: Since: 011112 Last Post: 976 days Last Active: 956 days 

 
Affected by 'Laziness' Position: Elite Since: 110810 From: in a grave Last Post: 22 days Last Active: 2 days 

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